Sort Colors
Problem
Given an array nums
with n
objects colored red, white, or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white, and blue.
We will use the integers 0
, 1
, and 2
to represent the color red, white, and blue, respectively.
You must solve this problem without using the library's sort function.
Example 1:
Input: nums = [2,0,2,1,1,0] Output: [0,0,1,1,2,2]
Example 2:
Input: nums = [2,0,1] Output: [0,1,2]
Constraints:
n == nums.length
1 <= n <= 300
nums[i]
is either0
,1
, or2
.
Solution
/**
* @param {number[]} nums
* @return {void} Do not return anything, modify nums in-place instead.
*/
var sortColors = function(nums) {
let l = 0; // pointer to end of 0s
let r = nums.length - 1; // pointers to start of 2s
for (let i = 0; i <= r; i++) {
if (nums[i] === 0) {
[nums[i], nums[l]] = [nums[l], nums[i]];
l++;
} else if (nums[i] === 2) {
[nums[i], nums[r]] = [nums[r], nums[i]];
r--;
i--; // might have swapped 0 to index i, so need to check again
}
}
};
We will implement a two pointers solution. Our solution is similar to the partition
method for quicksort. More specifically, we iterate through nums
while moving 0
s to index l
and 2
s to index r
. This pushes all 0
s to the start, 2
s to the end, and 1
s to the centre of nums
.