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Sort Colors

Problem

Given an array nums with n objects colored red, white, or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white, and blue.

We will use the integers 0, 1, and 2 to represent the color red, white, and blue, respectively.

You must solve this problem without using the library's sort function.

 

Example 1:

Input: nums = [2,0,2,1,1,0]
Output: [0,0,1,1,2,2]

Example 2:

Input: nums = [2,0,1]
Output: [0,1,2]

 

Constraints:

  • n == nums.length
  • 1 <= n <= 300
  • nums[i] is either 0, 1, or 2.

Solution

/**
* @param {number[]} nums
* @return {void} Do not return anything, modify nums in-place instead.
*/
var sortColors = function(nums) {
let l = 0; // pointer to end of 0s
let r = nums.length - 1; // pointers to start of 2s

for (let i = 0; i <= r; i++) {
if (nums[i] === 0) {
[nums[i], nums[l]] = [nums[l], nums[i]];
l++;
} else if (nums[i] === 2) {
[nums[i], nums[r]] = [nums[r], nums[i]];
r--;
i--; // might have swapped 0 to index i, so need to check again
}
}
};

We will implement a two pointers solution. Our solution is similar to the partition method for quicksort. More specifically, we iterate through nums while moving 0s to index l and 2s to index r. This pushes all 0s to the start, 2s to the end, and 1s to the centre of nums.