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Binary Tree Right Side View

Problem

Given the root of a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.

 

Example 1:

Input: root = [1,2,3,null,5,null,4]
Output: [1,3,4]

Example 2:

Input: root = [1,null,3]
Output: [1,3]

Example 3:

Input: root = []
Output: []

 

Constraints:

  • The number of nodes in the tree is in the range [0, 100].
  • -100 <= Node.val <= 100

Solution

/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[]}
*/
var rightSideView = function(root) {
const queue = root ? [root] : [];
const res = [];

while (queue.length) {
const n = queue.length;
res.push(queue[n - 1].val);
for (let i = 0; i < n; i++) {
const node = queue.shift();

if (node.left) {
queue.push(node.left);
}
if (node.right) {
queue.push(node.right);
}
}
}
return res;
};

We will implement a BFS solution. We do a level order traversal on root, and add the last node of each level to res (ie. the last node is the right view of each level).