Binary Tree Right Side View
Problem
Given the root
of a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.
Example 1:
Input: root = [1,2,3,null,5,null,4] Output: [1,3,4]
Example 2:
Input: root = [1,null,3] Output: [1,3]
Example 3:
Input: root = [] Output: []
Constraints:
- The number of nodes in the tree is in the range
[0, 100]
. -100 <= Node.val <= 100
Solution
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[]}
*/
var rightSideView = function(root) {
const queue = root ? [root] : [];
const res = [];
while (queue.length) {
const n = queue.length;
res.push(queue[n - 1].val);
for (let i = 0; i < n; i++) {
const node = queue.shift();
if (node.left) {
queue.push(node.left);
}
if (node.right) {
queue.push(node.right);
}
}
}
return res;
};
We will implement a BFS solution. We do a level order traversal on root
, and add the last node of each level to res
(ie. the last node is the right view of each level).