Remove Duplicates from Sorted List
Problem
Given the head
of a sorted linked list, delete all duplicates such that each element appears only once. Return the linked list sorted as well.
Example 1:
Input: head = [1,1,2] Output: [1,2]
Example 2:
Input: head = [1,1,2,3,3] Output: [1,2,3]
Constraints:
- The number of nodes in the list is in the range
[0, 300]
. -100 <= Node.val <= 100
- The list is guaranteed to be sorted in ascending order.
Solution
/**
* Definition for singly-linked list.
* function ListNode(val, next) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
*/
/**
* @param {ListNode} head
* @return {ListNode}
*/
var deleteDuplicates = function(head) {
cur = head;
while (cur?.next) {
if (cur.val === cur.next.val) {
cur.next = cur.next.next;
} else {
cur = cur.next;
}
}
return head;
};
Since the list is sorted, check if the next node has the same value as the current node, if so, skip the next node.