Palindrome Number
Problem
Given an integer x
, return true
if x
is palindrome integer.
An integer is a palindrome when it reads the same backward as forward.
- For example,
121
is a palindrome while123
is not.
Example 1:
Input: x = 121 Output: true Explanation: 121 reads as 121 from left to right and from right to left.
Example 2:
Input: x = -121 Output: false Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
Example 3:
Input: x = 10 Output: false Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
Constraints:
-231 <= x <= 231 - 1
Solution
/**
* @param {number} x
* @return {boolean}
*/
var isPalindrome = function(x) {
return x === parseInt(x.toString().split("").reverse().join(""));
};
We convert x
to a string, reverse it, convert it back to an integer, and check if it still equals x
.
Follow-up
Could you solve it without converting the integer to a string?
Solution
/**
* @param {number} x
* @return {boolean}
*/
var isPalindrome = function(x) {
if (x < 0) {
return false;
}
let y = x;
let reverse = 0;
while (y !== 0) {
reverse *= 10;
reverse += y % 10;
y = Math.floor(y / 10);
}
return reverse === x;
};
We reverse x
using division and check if the reverse still equals x
.